Water Resources & Irrigation interview questions

1. A.channel is non-silting non-scouring at critical velocity Vo = 0.55 m y^0.64, with m the critical velocity ratio depending on silt grade
2. B.a channel carrying its own silt attains a regime section where silt factor f = 1.76 √d and velocity is (Q f²/140)^(1/6)
3. C.delta is total water depth a crop needs over its base period, duty is area irrigated per cumec, and D = 8.64 B/Δ
4. D.dam checked against overturning, sliding along the base with a shear-friction factor, and crushing at the toe, with uplift reducing effective weight

Answer + AI explanation with Pro

1. A.Kennedy's theory
2. B.Duty and delta
3. C.Lacey's regime theory
4. D.Gravity dam stability

Answer + AI explanation with Pro

1. A.Duty and delta — delta is total water depth a crop needs over its base period, duty is area irrigated per cumec, and D = 8.64 B/Δ
2. B.Duty and delta — direct runoff hydrograph from 1 cm of effective rainfall spread uniformly over the catchment in a unit duration, allowing linear superposition
3. C.Duty and delta — hydraulic gradient at the downstream end of a weir floor, GE = H/(d π √λ), kept to 1/5 to 1/7 in fine sand to prevent piping
4. D.Duty and delta — channel is non-silting non-scouring at critical velocity Vo = 0.55 m y^0.64, with m the critical velocity ratio depending on silt grade

Answer + AI explanation with Pro

1. A.monsoon crops such as rice and cotton sown June to October, versus winter crops such as wheat and gram sown October to March
2. B.peak runoff Q = C I A / 3.6 in cumecs with intensity in mm/h and area in km², valid for small catchments and durations equal to time of concentration
3. C.an aqueduct carries the canal over a drain, a super-passage carries the drain over the canal, and a level crossing lets them meet
4. D.a channel carrying its own silt attains a regime section where silt factor f = 1.76 √d and velocity is (Q f²/140)^(1/6)

Answer + AI explanation with Pro

1. A.Unit hydrograph
2. B.Khosla's exit gradient
3. C.Lacey's regime theory
4. D.Kharif vs Rabi

Answer + AI explanation with Pro

1. A.Kharif vs Rabi — plotting cumulative inflow against time and drawing demand lines tangent to peaks to find the reservoir storage needed for a given yield
2. B.Kharif vs Rabi — monsoon crops such as rice and cotton sown June to October, versus winter crops such as wheat and gram sown October to March
3. C.Kharif vs Rabi — an aqueduct carries the canal over a drain, a super-passage carries the drain over the canal, and a level crossing lets them meet
4. D.Kharif vs Rabi — delta is total water depth a crop needs over its base period, duty is area irrigated per cumec, and D = 8.64 B/Δ

Answer + AI explanation with Pro

1. A.peak runoff Q = C I A / 3.6 in cumecs with intensity in mm/h and area in km², valid for small catchments and durations equal to time of concentration
2. B.an aqueduct carries the canal over a drain, a super-passage carries the drain over the canal, and a level crossing lets them meet
3. C.plotting cumulative inflow against time and drawing demand lines tangent to peaks to find the reservoir storage needed for a given yield
4. D.direct runoff hydrograph from 1 cm of effective rainfall spread uniformly over the catchment in a unit duration, allowing linear superposition

Answer + AI explanation with Pro

1. A.Kharif vs Rabi
2. B.Gravity dam stability
3. C.Kennedy's theory
4. D.Cross drainage works

Answer + AI explanation with Pro

1. A.Cross drainage works — peak runoff Q = C I A / 3.6 in cumecs with intensity in mm/h and area in km², valid for small catchments and durations equal to time of concentration
2. B.Cross drainage works — an aqueduct carries the canal over a drain, a super-passage carries the drain over the canal, and a level crossing lets them meet
3. C.Cross drainage works — direct runoff hydrograph from 1 cm of effective rainfall spread uniformly over the catchment in a unit duration, allowing linear superposition
4. D.Cross drainage works — plotting cumulative inflow against time and drawing demand lines tangent to peaks to find the reservoir storage needed for a given yield

Answer + AI explanation with Pro

1. A.direct runoff hydrograph from 1 cm of effective rainfall spread uniformly over the catchment in a unit duration, allowing linear superposition
2. B.peak runoff Q = C I A / 3.6 in cumecs with intensity in mm/h and area in km², valid for small catchments and durations equal to time of concentration
3. C.monsoon crops such as rice and cotton sown June to October, versus winter crops such as wheat and gram sown October to March
4. D.channel is non-silting non-scouring at critical velocity Vo = 0.55 m y^0.64, with m the critical velocity ratio depending on silt grade

Answer + AI explanation with Pro

1. A.Gravity dam stability
2. B.Kharif vs Rabi
3. C.Rational formula
4. D.Unit hydrograph

Answer + AI explanation with Pro

1. A.Rational formula — an aqueduct carries the canal over a drain, a super-passage carries the drain over the canal, and a level crossing lets them meet
2. B.Rational formula — direct runoff hydrograph from 1 cm of effective rainfall spread uniformly over the catchment in a unit duration, allowing linear superposition
3. C.Rational formula — monsoon crops such as rice and cotton sown June to October, versus winter crops such as wheat and gram sown October to March
4. D.Rational formula — peak runoff Q = C I A / 3.6 in cumecs with intensity in mm/h and area in km², valid for small catchments and durations equal to time of concentration

Answer + AI explanation with Pro

1. A.dam checked against overturning, sliding along the base with a shear-friction factor, and crushing at the toe, with uplift reducing effective weight
2. B.channel is non-silting non-scouring at critical velocity Vo = 0.55 m y^0.64, with m the critical velocity ratio depending on silt grade
3. C.a channel carrying its own silt attains a regime section where silt factor f = 1.76 √d and velocity is (Q f²/140)^(1/6)
4. D.plotting cumulative inflow against time and drawing demand lines tangent to peaks to find the reservoir storage needed for a given yield

Answer + AI explanation with Pro

1. A.Kennedy's theory
2. B.Rational formula
3. C.Gravity dam stability
4. D.Duty and delta

Answer + AI explanation with Pro

1. A.Kennedy's theory — hydraulic gradient at the downstream end of a weir floor, GE = H/(d π √λ), kept to 1/5 to 1/7 in fine sand to prevent piping
2. B.Kennedy's theory — channel is non-silting non-scouring at critical velocity Vo = 0.55 m y^0.64, with m the critical velocity ratio depending on silt grade
3. C.Kennedy's theory — a channel carrying its own silt attains a regime section where silt factor f = 1.76 √d and velocity is (Q f²/140)^(1/6)
4. D.Kennedy's theory — peak runoff Q = C I A / 3.6 in cumecs with intensity in mm/h and area in km², valid for small catchments and durations equal to time of concentration

Answer + AI explanation with Pro

1. A.monsoon crops such as rice and cotton sown June to October, versus winter crops such as wheat and gram sown October to March
2. B.peak runoff Q = C I A / 3.6 in cumecs with intensity in mm/h and area in km², valid for small catchments and durations equal to time of concentration
3. C.an aqueduct carries the canal over a drain, a super-passage carries the drain over the canal, and a level crossing lets them meet
4. D.a channel carrying its own silt attains a regime section where silt factor f = 1.76 √d and velocity is (Q f²/140)^(1/6)

Answer + AI explanation with Pro

1. A.Duty and delta
2. B.Khosla's exit gradient
3. C.Gravity dam stability
4. D.Lacey's regime theory

Answer + AI explanation with Pro

1. A.Lacey's regime theory — a channel carrying its own silt attains a regime section where silt factor f = 1.76 √d and velocity is (Q f²/140)^(1/6)
2. B.Lacey's regime theory — direct runoff hydrograph from 1 cm of effective rainfall spread uniformly over the catchment in a unit duration, allowing linear superposition
3. C.Lacey's regime theory — monsoon crops such as rice and cotton sown June to October, versus winter crops such as wheat and gram sown October to March
4. D.Lacey's regime theory — dam checked against overturning, sliding along the base with a shear-friction factor, and crushing at the toe, with uplift reducing effective weight

Answer + AI explanation with Pro

1. A.a channel carrying its own silt attains a regime section where silt factor f = 1.76 √d and velocity is (Q f²/140)^(1/6)
2. B.channel is non-silting non-scouring at critical velocity Vo = 0.55 m y^0.64, with m the critical velocity ratio depending on silt grade
3. C.direct runoff hydrograph from 1 cm of effective rainfall spread uniformly over the catchment in a unit duration, allowing linear superposition
4. D.plotting cumulative inflow against time and drawing demand lines tangent to peaks to find the reservoir storage needed for a given yield

Answer + AI explanation with Pro

1. A.Kharif vs Rabi
2. B.Gravity dam stability
3. C.Cross drainage works
4. D.Unit hydrograph

Answer + AI explanation with Pro

1. A.Unit hydrograph — direct runoff hydrograph from 1 cm of effective rainfall spread uniformly over the catchment in a unit duration, allowing linear superposition
2. B.Unit hydrograph — plotting cumulative inflow against time and drawing demand lines tangent to peaks to find the reservoir storage needed for a given yield
3. C.Unit hydrograph — monsoon crops such as rice and cotton sown June to October, versus winter crops such as wheat and gram sown October to March
4. D.Unit hydrograph — hydraulic gradient at the downstream end of a weir floor, GE = H/(d π √λ), kept to 1/5 to 1/7 in fine sand to prevent piping

Answer + AI explanation with Pro

1. A.delta is total water depth a crop needs over its base period, duty is area irrigated per cumec, and D = 8.64 B/Δ
2. B.a channel carrying its own silt attains a regime section where silt factor f = 1.76 √d and velocity is (Q f²/140)^(1/6)
3. C.plotting cumulative inflow against time and drawing demand lines tangent to peaks to find the reservoir storage needed for a given yield
4. D.peak runoff Q = C I A / 3.6 in cumecs with intensity in mm/h and area in km², valid for small catchments and durations equal to time of concentration

Answer + AI explanation with Pro

1. A.Duty and delta
2. B.Mass curve method
3. C.Gravity dam stability
4. D.Khosla's exit gradient

Answer + AI explanation with Pro

1. A.Mass curve method — plotting cumulative inflow against time and drawing demand lines tangent to peaks to find the reservoir storage needed for a given yield
2. B.Mass curve method — channel is non-silting non-scouring at critical velocity Vo = 0.55 m y^0.64, with m the critical velocity ratio depending on silt grade
3. C.Mass curve method — monsoon crops such as rice and cotton sown June to October, versus winter crops such as wheat and gram sown October to March
4. D.Mass curve method — delta is total water depth a crop needs over its base period, duty is area irrigated per cumec, and D = 8.64 B/Δ

Answer + AI explanation with Pro

1. A.monsoon crops such as rice and cotton sown June to October, versus winter crops such as wheat and gram sown October to March
2. B.a channel carrying its own silt attains a regime section where silt factor f = 1.76 √d and velocity is (Q f²/140)^(1/6)
3. C.hydraulic gradient at the downstream end of a weir floor, GE = H/(d π √λ), kept to 1/5 to 1/7 in fine sand to prevent piping
4. D.plotting cumulative inflow against time and drawing demand lines tangent to peaks to find the reservoir storage needed for a given yield

Answer + AI explanation with Pro

1. A.Kharif vs Rabi
2. B.Gravity dam stability
3. C.Lacey's regime theory
4. D.Khosla's exit gradient

Answer + AI explanation with Pro

1. A.Khosla's exit gradient — hydraulic gradient at the downstream end of a weir floor, GE = H/(d π √λ), kept to 1/5 to 1/7 in fine sand to prevent piping
2. B.Khosla's exit gradient — channel is non-silting non-scouring at critical velocity Vo = 0.55 m y^0.64, with m the critical velocity ratio depending on silt grade
3. C.Khosla's exit gradient — plotting cumulative inflow against time and drawing demand lines tangent to peaks to find the reservoir storage needed for a given yield
4. D.Khosla's exit gradient — monsoon crops such as rice and cotton sown June to October, versus winter crops such as wheat and gram sown October to March

Answer + AI explanation with Pro

1. A.dam checked against overturning, sliding along the base with a shear-friction factor, and crushing at the toe, with uplift reducing effective weight
2. B.an aqueduct carries the canal over a drain, a super-passage carries the drain over the canal, and a level crossing lets them meet
3. C.peak runoff Q = C I A / 3.6 in cumecs with intensity in mm/h and area in km², valid for small catchments and durations equal to time of concentration
4. D.delta is total water depth a crop needs over its base period, duty is area irrigated per cumec, and D = 8.64 B/Δ

Answer + AI explanation with Pro

1. A.Mass curve method
2. B.Cross drainage works
3. C.Duty and delta
4. D.Gravity dam stability

Answer + AI explanation with Pro

1. A.Gravity dam stability — hydraulic gradient at the downstream end of a weir floor, GE = H/(d π √λ), kept to 1/5 to 1/7 in fine sand to prevent piping
2. B.Gravity dam stability — delta is total water depth a crop needs over its base period, duty is area irrigated per cumec, and D = 8.64 B/Δ
3. C.Gravity dam stability — a channel carrying its own silt attains a regime section where silt factor f = 1.76 √d and velocity is (Q f²/140)^(1/6)
4. D.Gravity dam stability — dam checked against overturning, sliding along the base with a shear-friction factor, and crushing at the toe, with uplift reducing effective weight

Answer + AI explanation with Pro